在线编译器 C

#include <stdio.h> int counter(char s[]){ int counter = 0; int start = 0, end = 0; int i=0; while(s[i]!='\0'){ if(i!=0){ i++; } if(s[start]==s[end] && start!=end){ counter++; } while(s[i]!=' '){ end=s[i]; i++; } } return counter; } int main() { char a[1001]; scanf("%[^\n]", a); printf("%d", counter(a)); return 0; }
This code attempts to count something in a string, but it has several logical issues. The function `counter` is supposed to process words in a string, but the loops and conditions are not correctly structured. The variable `end` is being assigned a character value instead of an index, and the logic for comparing characters is flawed.

- The variable `end` is being assigned `s[i]` which is a character, not an index. You likely intended `end` to track the position of the last character in a word, so it should be an integer index like `start`.
- The condition `if(s[start]==s[end] && start!=end)` compares characters at positions, but `start` and `end` are not updated correctly to point to the beginning and end of each word. Think about how to reset `start` and `end` for each new word after a space.