#include <stdio.h>
void print_times(int m, int times) {
if (times == 0) {
return;
}
printf("%d ", m);
print_times(m, times - 1);
}
int current = 1;
void print_sequence(int n) {
if (n <= 0) {
return;
}
if (n >= current) {
print_times(current, current);
print_sequence(n - current);
current++;
} else {
print_times(current, n);
}
}
int main() {
int x;
scanf("%d", &x);
print_sequence(x);
return 0;
}
This code prints a sequence of numbers where each number appears a certain number of times. The function `print_times` prints the number `m` exactly `times` times. The function `print_sequence` uses a global variable `current` to decide which number to print next and how many times. It tries to print `current` repeated `current` times, then subtracts that count from `n` and increments `current`. If `n` is smaller than `current`, it prints `current` only `n` times.
- The global variable `current` is modified inside `print_sequence`, but its value persists across recursive calls. Check if the logic for updating `current` and subtracting from `n` correctly handles the case when `n` is not exactly a sum of consecutive numbers like 1 + 2 + 3 + ... . For example, if `x` is 5, what sequence do you expect, and what does the code produce?
- The condition `if (n >= current)` uses the current value of `current` before it is incremented. Trace through a small example like `x = 2` step by step to see if the recursion and the increment of `current` work as intended.