This code reads 10 integers into an array, reverses the array in place, and then prints the reversed array. However, there is a problem in the printing loop that causes the program to exit early. - The `return 0;` statement is placed inside the last `for` loop, so the loop only runs once and the program ends after printing just the first element of the reversed array. Move the `return 0;` outside the loop, after the closing brace of the loop.