Онлайн компилятор C

#include <stdio.h> //#include <string.h> int main(void) { char s[205]; int count = 0; char c; while (scanf("%c", &c) == 1) { if (c ==\n) break; if (c >= '0' && c <= '9') { count++; } } printf("%d", count); return 0; }
The code reads characters from input one by one and counts how many are digits (0-9). It stops reading when a newline character is encountered. However, there is a syntax error in the condition checking for the newline.

- The condition `if (c ==\n)` is missing quotes around the newline character. In C, character literals must be enclosed in single quotes, so it should be `if (c == '\n')`.
- The commented out `#include <string.h>` is not needed for this code, but including it would not cause harm.