Online Compiler Nasm

extern io_get_dec, io_print_dec, io_print_char section .bss table_1 resd 10000 table_2 resd 10000 n resd 1 m resd 1 k resd 1 section .text global main main: call io_get_dec mov [n], eax call io_get_dec mov [m], eax call io_get_dec mov [k], eax xor ecx, ecx ; счетчик индекса от 0 до n*m-1 mov eax, [n] mul dword [m] ; eax = n * m mov edi, eax ; edi = общее количество элементов .fill_loop: cmp ecx, edi jge .print_table call io_get_dec mov [table_1 + 4 * ecx], eax inc ecx jmp .fill_loop .print_table: xor ecx, ecx ; счетчик индекса от 0 до n*m-1 mov eax, [n] mul dword [m] ; eax = n * m mov edi, eax ; edi = общее количество элементов .print_loop: cmp ecx, edi jge .done call io_print_dec mov [table_1 + 4 * ecx], eax inc ecx jmp .print_loop .done: xor eax, eax ret
1) This code reads three integers (n, m, k), fills a table with n*m integer inputs, and then attempts to print them. However, there is a critical bug in the print loop where it calls `io_print_dec` without loading the value to print into EAX first, and it also incorrectly overwrites the table with the return value from `io_print_dec`.

2) Hint 1: In the `.print_loop`, you need to load the value from `table_1` into EAX *before* calling `io_print_dec`. The current order is backwards.
Hint 2: The instruction `mov [table_1 + 4 * ecx], eax` inside the print loop is destructive and unnecessary. You should remove it or replace it with logic that only prints the value.