#include <stdio.h>
int main() {
int A[10];
for (int i = 0; i < 10; i++) {
scanf("%d", &A[i]);
}
int max = A[0];
int maxx = A[0];
for (int i = 1; i < 10; i++) {
if (A[i] > max) {
max = A[i]; // find max
}
maxx = A[0];
for (int i = 1; i < 10; i++) {
if (A[i] > maxx && A[i] < max) {
maxx = A[i]; // find second biggest
}
}
if (maxx == max) {
maxx = max;
}
printf("%d\n", max + maxx);
return 0;
}
This code reads 10 integers into an array, then attempts to find the largest and second largest values and print their sum. However, the logic for finding the second largest is incorrectly placed inside the loop for finding the largest, and the loops are nested in a way that will not work as intended.
- The inner loop that tries to find the second largest is placed inside the outer loop that finds the largest. This means the inner loop runs multiple times unnecessarily, and it resets `maxx` to `A[0]` each time the outer loop iterates. Consider moving the second largest search to after the largest is fully determined, and make sure it is a separate loop, not nested inside the first loop.
- The condition `if (maxx == max)` and setting `maxx = max` suggests you are trying to handle the case where all numbers are equal. But this assignment does not solve the problem correctly because if all numbers are equal, the second largest should also be equal to the largest. Think about what value `maxx` should have in that case, and whether your current approach correctly finds it.