Code Bot compiler - Online Compiler C. This code reads two strings and tries to find the first position where they differ, but it has several logical errors. The loop condition and the initial assignments to `s1[len1]` and `s2[len2]` are incorrect. - The lines `s1[len1]='\0';` and `s2[len2]...

Online Compiler C

#include <stdio.h> int main() { char s1[1001], s2[1001]; fgets(s1, sizeof(s1), stdin); fgets(s2, sizeof(s2), stdin); int len1 = 0; int len2 = 0; s1[len1]='\0'; s2[len2]='\0'; int i=0; while(s1[i]=='\0'&&s2[i]!='\0'){ if (s1[i] != s2[i]) { printf("%d\n", i); return 0; } i++; } if (s1[i] == '\0' && s2[i] == '\0') { printf("-1\n"); } else { printf("%d\n", i); } return 0; }

This code reads two strings and tries to find the first position where they differ, but it has several logical errors. The loop condition and the initial assignments to `s1[len1]` and `s2[len2]` are incorrect.

- The lines `s1[len1]='\0';` and `s2[len2]='\0';` set the first character of each string to the null terminator, which erases the actual input. You should not modify the strings before comparing them.
- The loop condition `while(s1[i]=='\0'&&s2[i]!='\0')` is wrong. It checks if the first character of `s1` is null, which will be true after the previous assignment, and then the loop never runs. You need a condition that continues while both strings have characters and they are equal.