#include <stdio.h>
void print_times(int m, int times) {
if (times == 0) {
return;
}
printf("%d ", m);
print_times(m, times - 1);
}
void print_sequence(int n) {
int current = 1;
if (n <= 0) {
return;
}
if (n >= current) {
print_times(current, current);
print_sequence(n - current);
current++;
} else {
print_times(current, n);
}
}
int main() {
int x;
scanf("%d", &x);
print_sequence(x);
return 0;
}
This code attempts to print a sequence of numbers where each number appears as many times as its value, but it has a logic error. The function `print_sequence` is supposed to print numbers from 1 upward, each repeated that many times, until the total count reaches `n`. However, the variable `current` is reset to 1 on every recursive call, so the intended increment never happens.
- The variable `current` is declared inside `print_sequence` and set to 1 each time the function is called. This means the recursion always tries to print the number 1 again, instead of moving to the next number.
- The condition `if (n >= current)` will always be true when `current` is 1 and `n` is positive, so the `else` branch is never reached. The recursion subtracts `current` (which is always 1) from `n`, so it only prints the number 1 repeatedly.